"Aristoteles" meaning in All languages combined

See Aristoteles on Wiktionary

Proper name [德語]

IPA: /aʁɪsˈtoːtələs/, /-lɛs/ Audio: De-Aristoteles.ogg Forms: Aristoteles', Aristotelis, Aristoteles
Etymology: 借自拉丁語 Aristotelēs,派生自古希臘語 Ἀριστοτέλης (Aristotélēs)。
  1. 亞里士多德(古希臘哲學家)
    Sense id: zh-Aristoteles-de-name-bma1Go8V
The following are not (yet) sense-disambiguated

Proper name [拉丁語]

Forms: Aristotelis, Aristotelī
Etymology: 借自古希臘語 Ἀριστοτέλης (Aristotélēs)。
  1. 亞里士多德(古希臘哲學家)
    Sense id: zh-Aristoteles-la-name-bma1Go8V
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "德語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "德語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自拉丁語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自拉丁語的德語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自拉丁語 Aristotelēs,派生自古希臘語 Ἀριστοτέλης (Aristotélēs)。",
  "forms": [
    {
      "form": "Aristoteles'",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Aristotelis",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Aristoteles",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "德語",
  "lang_code": "de",
  "pos": "name",
  "raw_tags": [
    "專有名詞",
    "強變化"
  ],
  "senses": [
    {
      "glosses": [
        "亞里士多德(古希臘哲學家)"
      ],
      "id": "zh-Aristoteles-de-name-bma1Go8V"
    }
  ],
  "sounds": [
    {
      "ipa": "/aʁɪsˈtoːtələs/"
    },
    {
      "ipa": "/-lɛs/"
    },
    {
      "audio": "De-Aristoteles.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c9/De-Aristoteles.ogg/De-Aristoteles.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-Aristoteles.ogg",
      "raw_tags": [
        "Audio"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Aristoteles"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語第三類變格名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語第三類變格陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的拉丁語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自古希臘語 Ἀριστοτέλης (Aristotélēs)。",
  "forms": [
    {
      "form": "Aristotelis",
      "raw_tags": [
        "属格"
      ]
    },
    {
      "form": "Aristotelī",
      "raw_tags": [
        "属格"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "亞里士多德(古希臘哲學家)"
      ],
      "id": "zh-Aristoteles-la-name-bma1Go8V"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Aristoteles"
}
{
  "categories": [
    "德語專有名詞",
    "德語詞元",
    "有2個詞條的頁面",
    "派生自古希臘語的意大利語詞",
    "派生自拉丁語的德語詞",
    "源自拉丁語的德語借詞"
  ],
  "etymology_text": "借自拉丁語 Aristotelēs,派生自古希臘語 Ἀριστοτέλης (Aristotélēs)。",
  "forms": [
    {
      "form": "Aristoteles'",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Aristotelis",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Aristoteles",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "德語",
  "lang_code": "de",
  "pos": "name",
  "raw_tags": [
    "專有名詞",
    "強變化"
  ],
  "senses": [
    {
      "glosses": [
        "亞里士多德(古希臘哲學家)"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/aʁɪsˈtoːtələs/"
    },
    {
      "ipa": "/-lɛs/"
    },
    {
      "audio": "De-Aristoteles.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c9/De-Aristoteles.ogg/De-Aristoteles.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-Aristoteles.ogg",
      "raw_tags": [
        "Audio"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Aristoteles"
}

{
  "categories": [
    "拉丁語專有名詞",
    "拉丁語第三類變格名詞",
    "拉丁語第三類變格陽性名詞",
    "拉丁語詞元",
    "拉丁語陽性名詞",
    "有2個詞條的頁面",
    "派生自古希臘語的拉丁語詞",
    "源自古希臘語的拉丁語借詞"
  ],
  "etymology_text": "借自古希臘語 Ἀριστοτέλης (Aristotélēs)。",
  "forms": [
    {
      "form": "Aristotelis",
      "raw_tags": [
        "属格"
      ]
    },
    {
      "form": "Aristotelī",
      "raw_tags": [
        "属格"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "亞里士多德(古希臘哲學家)"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Aristoteles"
}

Download raw JSONL data for Aristoteles meaning in All languages combined (1.6kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-05 from the zhwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.